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<meta name="description" content="签到emmm,签到。 Snake一开始以为这题改一改user.xml就行了，然后才发现自己太天真了。直接解压jar包，审计源码。在Game.class文件中发现flag输出部分12345678910111213141516171819202122if (this.score &amp;gt;= 500 &amp;amp;&amp;amp; this.isshow) &amp;#123;     String flag = &quot;eo">
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<meta property="og:description" content="签到emmm,签到。 Snake一开始以为这题改一改user.xml就行了，然后才发现自己太天真了。直接解压jar包，审计源码。在Game.class文件中发现flag输出部分12345678910111213141516171819202122if (this.score &amp;gt;= 500 &amp;amp;&amp;amp; this.isshow) &amp;#123;     String flag = &quot;eo">
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<meta name="twitter:description" content="签到emmm,签到。 Snake一开始以为这题改一改user.xml就行了，然后才发现自己太天真了。直接解压jar包，审计源码。在Game.class文件中发现flag输出部分12345678910111213141516171819202122if (this.score &amp;gt;= 500 &amp;amp;&amp;amp; this.isshow) &amp;#123;     String flag = &quot;eo">



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          <h1 class="post-title" itemprop="name headline">CTF论剑场MISC篇</h1>
        

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        <h2 id="签到"><a href="#签到" class="headerlink" title="签到"></a>签到</h2><p>emmm,签到。</p>
<h2 id="Snake"><a href="#Snake" class="headerlink" title="Snake"></a>Snake</h2><p>一开始以为这题改一改user.xml就行了，然后才发现自己太天真了。<br>直接解压jar包，审计源码。<br>在Game.class文件中发现flag输出部分<br><figure class="highlight java"><table><tr><td class="gutter"><pre><span class="line">1</span><br><span class="line">2</span><br><span class="line">3</span><br><span class="line">4</span><br><span class="line">5</span><br><span class="line">6</span><br><span class="line">7</span><br><span class="line">8</span><br><span class="line">9</span><br><span class="line">10</span><br><span class="line">11</span><br><span class="line">12</span><br><span class="line">13</span><br><span class="line">14</span><br><span class="line">15</span><br><span class="line">16</span><br><span class="line">17</span><br><span class="line">18</span><br><span class="line">19</span><br><span class="line">20</span><br><span class="line">21</span><br><span class="line">22</span><br></pre></td><td class="code"><pre><span class="line"><span class="keyword">if</span> (<span class="keyword">this</span>.score &gt;= <span class="number">500</span> &amp;&amp; <span class="keyword">this</span>.isshow) &#123;</span><br><span class="line">     String flag = <span class="string">"eobdxpmbhf\\jpgYaiibYagkc&#123;"</span>;</span><br><span class="line">     <span class="keyword">int</span> key = <span class="keyword">this</span>.snake.len - <span class="keyword">this</span>.score;</span><br><span class="line">     String xx = <span class="string">""</span>;</span><br><span class="line"></span><br><span class="line">     <span class="keyword">int</span> i;</span><br><span class="line">     <span class="keyword">char</span> c;</span><br><span class="line">     <span class="keyword">for</span>(i = <span class="number">0</span>; i &lt; flag.length() / <span class="number">2</span>; ++i) &#123;</span><br><span class="line">         c = flag.charAt(i);</span><br><span class="line">         c = (<span class="keyword">char</span>)(c ^ key);</span><br><span class="line">         xx = xx + c;</span><br><span class="line">     &#125;</span><br><span class="line"></span><br><span class="line">     <span class="keyword">for</span>(i = flag.length() / <span class="number">2</span> + <span class="number">1</span>; i &lt; flag.length(); ++i) &#123;</span><br><span class="line">         c = flag.charAt(i);</span><br><span class="line">         c = (<span class="keyword">char</span>)(c ^ key * <span class="number">2</span>);</span><br><span class="line">         xx = xx + c;</span><br><span class="line">     &#125;</span><br><span class="line"></span><br><span class="line">     JOptionPane.showInputDialog((Component)<span class="keyword">null</span>, <span class="string">"This is your flag CALCULATE BY YOUR SCORE:\n"</span>, <span class="string">"Congratulations"</span>, -<span class="number">1</span>, (Icon)<span class="keyword">null</span>, (Object[])<span class="keyword">null</span>, xx);</span><br><span class="line">     <span class="keyword">this</span>.isshow = <span class="keyword">false</span>;</span><br><span class="line"> &#125;</span><br></pre></td></tr></table></figure></p>
<a id="more"></a>
<p>一个解密输出flag的过程，我们复现一下就行了。需要改动的代码不多，一个是直接令key=3（因为len永远比score大3），还有一个就是输出。<br>上payload<br><figure class="highlight java"><table><tr><td class="gutter"><pre><span class="line">1</span><br><span class="line">2</span><br><span class="line">3</span><br><span class="line">4</span><br><span class="line">5</span><br><span class="line">6</span><br><span class="line">7</span><br><span class="line">8</span><br><span class="line">9</span><br><span class="line">10</span><br><span class="line">11</span><br><span class="line">12</span><br><span class="line">13</span><br><span class="line">14</span><br><span class="line">15</span><br><span class="line">16</span><br><span class="line">17</span><br><span class="line">18</span><br><span class="line">19</span><br><span class="line">20</span><br><span class="line">21</span><br><span class="line">22</span><br><span class="line">23</span><br><span class="line">24</span><br></pre></td><td class="code"><pre><span class="line"></span><br><span class="line"><span class="keyword">public</span> <span class="class"><span class="keyword">class</span> <span class="title">main</span></span>&#123;</span><br><span class="line">    <span class="function"><span class="keyword">public</span> <span class="keyword">static</span> <span class="keyword">void</span> <span class="title">main</span><span class="params">(String[] args)</span> </span>&#123;</span><br><span class="line">        String flag = <span class="string">"eobdxpmbhf\\jpgYaiibYagkc&#123;"</span>;</span><br><span class="line">        <span class="keyword">int</span> key = <span class="number">3</span>;</span><br><span class="line">        String xx = <span class="string">""</span>;</span><br><span class="line"></span><br><span class="line">        <span class="keyword">int</span> i;</span><br><span class="line">        <span class="keyword">char</span> c;</span><br><span class="line">        <span class="keyword">for</span>(i = <span class="number">0</span>; i &lt; flag.length() / <span class="number">2</span>; ++i) &#123;</span><br><span class="line">            c = flag.charAt(i);</span><br><span class="line">            c = (<span class="keyword">char</span>)(c ^ key);</span><br><span class="line">            xx = xx + c;</span><br><span class="line">        &#125;</span><br><span class="line"></span><br><span class="line">        <span class="keyword">for</span>(i = flag.length() / <span class="number">2</span> + <span class="number">1</span>; i &lt; flag.length(); ++i) &#123;</span><br><span class="line">            c = flag.charAt(i);</span><br><span class="line">            c = (<span class="keyword">char</span>)(c ^ key * <span class="number">2</span>);</span><br><span class="line">            xx = xx + c;</span><br><span class="line">        &#125;</span><br><span class="line">        System.out.println(xx);</span><br><span class="line"><span class="comment">//        JOptionPane.showInputDialog((Component)null, "This is your flag CALCULATE BY YOUR SCORE:\n", "Congratulations", -1, (Icon)null, (Object[])null, xx);</span></span><br><span class="line">    &#125;</span><br><span class="line">&#125;</span><br></pre></td></tr></table></figure></p>
<h2 id="头像"><a href="#头像" class="headerlink" title="头像"></a>头像</h2><p>查看二进制源码，其中有一个flag，将其base64解密为ilovethegirl，然后根据题目要求，将其md5加密得flag。</p>
<h2 id="被截获的电报"><a href="#被截获的电报" class="headerlink" title="被截获的电报"></a>被截获的电报</h2><p>用au打开发现音频文件是莫尔斯电码，直接把密文放到解密网站解密就行了。</p>
<h2 id="esaypdf"><a href="#esaypdf" class="headerlink" title="esaypdf"></a>esaypdf</h2><p>从来没有做过关于pdf的题目，百度了一下，一种方式是通过weStego自动解密，完蛋，没用。另一种是一篇专利论文，通过pdf最后的偏移量来隐写数据，（我太难了）。<br>所以我猜想pdf里的照片存在隐写，想提取它（误操作），结果在移动图片时，发现图片下面就是flag！！！<br>emmm，真easy。</p>
<h2 id="损坏的图片"><a href="#损坏的图片" class="headerlink" title="损坏的图片"></a>损坏的图片</h2><p>查看图片，发现文件已损坏，结合题目猜测是缺少文件头，用010editor打开，在末尾发现倒置的png，即<code>GNP‰</code>，猜（肯）测（定）文件被倒写。<br>写个脚本逆回来。<br><figure class="highlight py"><table><tr><td class="gutter"><pre><span class="line">1</span><br><span class="line">2</span><br><span class="line">3</span><br><span class="line">4</span><br><span class="line">5</span><br><span class="line">6</span><br><span class="line">7</span><br><span class="line">8</span><br><span class="line">9</span><br><span class="line">10</span><br><span class="line">11</span><br><span class="line">12</span><br></pre></td><td class="code"><pre><span class="line">infile = open(<span class="string">'1.png'</span>, <span class="string">'rb'</span>)</span><br><span class="line">outfile = open(<span class="string">'2.png'</span>, <span class="string">'wb'</span>)</span><br><span class="line">b = []</span><br><span class="line">i = <span class="number">0</span></span><br><span class="line"><span class="keyword">while</span> <span class="literal">True</span>:</span><br><span class="line">    t = infile.read(<span class="number">1</span>)</span><br><span class="line">    b.append(t)</span><br><span class="line">    <span class="keyword">if</span> <span class="keyword">not</span> t:</span><br><span class="line">        <span class="keyword">break</span></span><br><span class="line">b = b[::<span class="number">-1</span>]</span><br><span class="line"><span class="keyword">for</span> j <span class="keyword">in</span> b:</span><br><span class="line">    outfile.write(j)</span><br></pre></td></tr></table></figure></p>
<p>输出图片是个二维码，扫描后得flag。</p>
<h2 id="0和1的故事"><a href="#0和1的故事" class="headerlink" title="0和1的故事"></a>0和1的故事</h2><p>emmm，这题营养不高。<br>打开三层压缩包，发现里面有一个txt文件，文件提示flag is not here，有点此地无银三百两的感觉，用010editor打开，发现可视文本后面有由0x09，0x20组成的字符串，该字符串在010中显示为. 组成的字符串，在txt中是不可见的。<br>由题目提示，将0x20换为0，0x09换为1，由此构成了一个新的数，将其转为十六进制就是flag了。<br>到这里就有点懵，咋就是答案了，emmm，出题人设计不够巧妙吧。</p>
<h2 id="怀疑人生"><a href="#怀疑人生" class="headerlink" title="怀疑人生"></a>怀疑人生</h2><p>首先分析ctf1.zip，用Ziperello字典破解得到密码<code>password</code>，解压压缩包，得到base64加密字符串，解密后再将其url解码得<code>flag{hacker</code>。<br>然后分析ctf2.jpg，用binwalk分析得到有zip隐写，使用foremost分离。得到一个txt文件，文件被okk！加密，逆向解密得到<code>3oD54e</code>字符串,再用base58解码得<code>misc</code>。<br>最后分析ctf3.jpg，一开始还在想怎么切割这个二维码，能让手机识别，结果<a href="https://online-barcode-reader.inliteresearch.com/" target="_blank" rel="noopener">这个网站</a>直接能识别，得到flag最后一部分<code>12580}</code><br>拼凑出来得flag</p>
<h2 id="向日葵"><a href="#向日葵" class="headerlink" title="向日葵"></a>向日葵</h2><p>感觉hint有点少。<br>首先binwalk分析照片，发现有rar压缩隐写，不懂为什么foremost提取不了，直接硬改。<br>得到txt文件，到这就不大会了，百度了一下wp。<br>解密方式是波利比奥斯方阵密码的魔改形式<br>密码表如下</p>
<table>
<thead>
<tr>
<th></th>
<th>1</th>
<th>2</th>
<th>3</th>
<th>4</th>
<th>5</th>
</tr>
</thead>
<tbody>
<tr>
<td>1</td>
<td>a</td>
<td>b</td>
<td>c</td>
<td>d</td>
<td>e</td>
</tr>
<tr>
<td>2</td>
<td>f</td>
<td>g</td>
<td>h</td>
<td>i</td>
<td>j</td>
</tr>
<tr>
<td>3</td>
<td>k</td>
<td>l</td>
<td>m</td>
<td>n</td>
<td>o</td>
</tr>
<tr>
<td>4</td>
<td>p</td>
<td>q</td>
<td>r</td>
<td>s</td>
<td>t</td>
</tr>
<tr>
<td>5</td>
<td>u</td>
<td>v</td>
<td>w</td>
<td>x</td>
<td>y/z</td>
</tr>
</tbody>
</table>
<p>对照密码表解密得<code>juijoldugjtfbtz</code><br>然后就是让人意想不到的操作，凯撒密码，遍历一遍，发现把所有字母向前挪一个，得flag</p>
<h2 id="进制转换"><a href="#进制转换" class="headerlink" title="进制转换"></a>进制转换</h2><p>盲猜四进制，ASCII码对照一下出flag</p>
<h2 id="txt500"><a href="#txt500" class="headerlink" title="txt500"></a>txt500</h2><p>直接在文件中搜索key关键词就行了，由于是多文件，所以要通过Linux或者windows下UE搜索。</p>
<p>## </p>

      
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